question_answer

A massive box is dragged along a horizontal floor by a rope. The rope makes an angle of \[\text{6}0{}^\circ \] with the horizontal. Then, find the amount of work done.

Answer:

Given, mass of the box \[(m)=mkg\] Displacement \[(S)=S\,\,m\] The rope makes an angle,\[\theta =60{}^\circ \] \[W=?\] We know, \[W=F\,\,S\,\,\cos \theta \] \[\Rightarrow W=F\times S\times \cos \,\,60{}^\circ \] \[=F\times S\times \frac{1}{2}\] \[\therefore \]The work done\[W=\frac{FS}{2}\]