Answer:
\[m=2\,kg\] \[V=0.1\,\,m/s=1\times {{10}^{-1}}m/s\] \[KE=?\] \[KE=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 2\times {{(1\times {{10}^{-1}})}^{2}}\] \[={{10}^{-2}}J\]
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