question_answer

If the velocity of a body is tripled, then find the % change in K.E

Answer:

% change in \[KE=\left( \frac{K{{E}_{2}}}{K{{E}_{1}}}-1 \right)\times 1\]b \[K{{E}_{2}}=\frac{1}{2}m{{(3V)}^{2}}=9\times \frac{1}{2}m{{v}^{2}}=9\,K{{E}_{1}}\] \[\Rightarrow %\,\,Change\,\,in\,\,KE=\left( \frac{9K{{E}_{1}}}{K{{E}_{1}}}-1 \right)\times 100=800\]