Answer:
\[{{1}^{st}}\,\,body=K{{E}_{1}}\frac{1}{2}m{{v}^{2}}\] \[{{2}^{nd}}\,\,body=K{{E}_{2}}=\frac{1}{2}(2m){{\left( \frac{V}{2} \right)}^{2}}\] \[=\frac{1}{2}2m\times \frac{{{V}^{2}}}{4}\] \[\frac{1}{2}m{{v}^{2}}\times \frac{1}{2}\] \[\Rightarrow K{{E}_{2}}=\frac{K{{E}_{1}}}{2}\]
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