Answer:
\[KE=\frac{{{P}^{2}}}{2m}\] \[\Rightarrow KE\propto \frac{1}{m}(\because P=Cons\tan t)\] \[\Rightarrow \frac{K{{E}_{1}}}{K{{E}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}\]
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