Answer:
\[KE=\frac{{{P}^{2}}}{2m}\Rightarrow P\propto \sqrt{KE\times m}\] \[\Rightarrow \frac{{{P}_{1}}}{{{P}_{2}}}=\sqrt{\frac{K{{E}_{1}}}{K{{E}_{2}}}\times \frac{{{m}_{1}}}{{{m}_{2}}}}\] \[\frac{{{P}_{1}}}{{{P}_{2}}}=\sqrt{\frac{8}{1}\times \frac{m}{2m}=\frac{2}{1}}\]
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