question_answer

A bag of rice weighs 200 kg. To what height should it be raised, so that its potential energy may be 9800 Joules? (Take \[\text{g}=\text{9}.\text{8m}{{\text{s}}^{-\text{2}}}\])

Answer:

\[m=200kg\] \[h=?\] \[\frac{60}{100}=\frac{\frac{w}{t}}{200}\] \[PE=9800\,J\] \[PE=mgh\] \[h=\frac{PE}{mg}=\frac{9800}{9.8\times 200}=\frac{1000}{200}=5m\]