Answer:
\[S=10\,m\] \[a=60{}^\circ \] \[F=5\,N\] \[w=?\] \[W=FS\,\,\cos \theta \] \[=5\times 10\times \cos \,\,60{}^\circ \] \[=5\times 10\times \frac{1}{2}=25\,J\]
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