Answer:
As the body reaches B the K.E. = P.E. at A.
As it moves to C there is also a loss in P.E. which is equal to\[mg{{h}_{1}}.\] The total loss of \[P.E.=mgh+mg{{h}_{1}}=\] \[(30\times 15\times 30\times 0.5)\] Work done\[=mg(h+{{h}_{1}})\] \[F\times 0.5=30\times 15.5\Rightarrow F=30\times 31=930N.\]
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