Answer:
Total mass of train \[=50\times 25=1250\,\,ton\] Total frictional force \[=1250\times 10=12500\,\,N\] Velocity \[=54\times \frac{5}{18}=15\,m{{s}^{-1}}\] \[Horse\,\,power=\frac{Frictinal\,\,force\,\,\,velocity}{746}=\] \[\frac{12500\times 15}{746}=251.3\,\,HP\]
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