Answer:
\[F=5N;\,\,S=6m;\,\,\theta =300;\,\,Work\,done=W=?\] We know that,\[W=FS\,\,\cos \theta =5\times 6\times \cos \,\,30=\] \[30\frac{\sqrt{3}}{2}=15\sqrt{3}J.\]
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