A) 5 : 4
B) 4 : 5
C) 1 : 4
D) 4 : 1
Correct Answer: C
Solution :
At highest point total energy \[(T.E)=mgh\] We have to find, K.E. : P.E. at height \[\frac{4th}{5}\] For this we have to find K.E. = ? and P.E. =? We know, \[P.E.=mgh\Rightarrow m\times g\times \frac{4h}{5}=\frac{4}{5}mgh\] We also know that, \[T.E.=K.E.+P.E.\] \[\Rightarrow mgh=K.E.+\frac{4}{5}mgh=\frac{1}{5}mgh\] \[\therefore \frac{K.E.}{P.E.}=\frac{\frac{1}{5}mgh}{\frac{4}{5}mgh}=\frac{1}{4}\] Therefore, \[K.E.=1:4\]You need to login to perform this action.
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