A) 1 J
B) 1.04 J
C) 3.5 J
D) 10 J
Correct Answer: D
Solution :
Given, \[m=0.1\,\,kg\,\,h=10m\,\,g=10m/{{s}^{2}}\] \[K.E.=?\] We know, \[K.E.=\frac{1}{2}m{{v}^{2}}\] ????..(1) For this first we have to find ?v? From the equation\[v=\sqrt{2gh}\] we get, \[v=\sqrt{2\times 10\times 10}=10\sqrt{2}\,m/s\] Applying the above values in equation (1) we get, \[K.E.=\frac{1}{2}\times 0.1\times {{(10\times \sqrt{2})}^{2}}=10\,J\]
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