A) 1 m
B) 1.5 m
C) 2 m
D) 9.8 m
Correct Answer: A
Solution :
\[ven\frac{1}{2}m{{u}^{2}}=196\] Again, \[mgh=\frac{1}{2}m({{u}^{2}}-2\,\,gh)\] \[\Rightarrow {{u}^{2}}-2gh=2gh\Rightarrow {{u}^{2}}=2gh+2gh\] \[\Rightarrow {{u}^{2}}=4gh\Rightarrow h=\frac{{{u}^{2}}}{4g}=\frac{2\times 196}{4\times 9.8}=10\,m\,\,or\]\[0.01\,\,cm\]You need to login to perform this action.
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