A) 3 : 4
B) 1 : 3
C) 4 : 3
D) 3 : 1
Correct Answer: B
Solution :
P.E at height\['h'=mgh\] P.E at height\[\frac{3h}{4}=\frac{3mgh}{4}\] K.E at the height of\[\frac{3h}{4}=P.E.\]at maximum height ?h? - P.E at the height \[\frac{3h}{4}=mgh-\frac{3mgh}{4}=\frac{1}{4}mgh\] \[\therefore \]Ratio between K.E and P.E at the height of 3h/4 \[=\frac{mgh\times 4}{4\times 3\,\,mgh}=1:3\]You need to login to perform this action.
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