A) 8280 V
B) 828 V
C) 82800 V
D) 8.28 V
Correct Answer: A
Solution :
\[eV=\frac{hc}{\lambda }=\frac{6.63\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.5\times {{10}^{-10}}}\] \[\Rightarrow V=\frac{6.63\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 1.5\times {{10}^{-10}}}\] =8280 Volt.You need to login to perform this action.
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