A) \[11.2\times {{10}^{-27}}\]
B) \[12.9\times {{10}^{-16}}\]
C) \[1.7\times {{10}^{-15}}\]
D) \[10\times {{10}^{-16}}\]
Correct Answer: B
Solution :
Required ionisation energy \[=\frac{hc}{\lambda }=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.54\times {{10}^{-10}}}\]J \[=12.9\times {{10}^{-16}}\]J
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