A) \[\frac{43}{29}\lambda \]
B) \[\frac{42}{28}\lambda \]
C) \[\frac{9}{4}\lambda \]
D) \[\frac{4}{9}\lambda \]
Correct Answer: C
Solution :
\[\lambda \,\propto \frac{1}{{{(Z-1)}^{2}}}\]\[\Rightarrow \frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}={{\left( \frac{{{Z}_{1}}-1}{{{Z}_{2}}-1} \right)}^{2}}\] \[\Rightarrow \frac{{{\lambda }_{2}}}{\lambda }={{\left( \frac{43-1}{29-1} \right)}^{2}}={{\left( \frac{42}{28} \right)}^{2}}\] Þ \[{{\lambda }_{2}}=\frac{9}{4}\lambda \].
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