JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank X Rays

  • question_answer
    The minimum frequency \[\nu \] of continuous X-rays is related to the applied potential difference V as

    A)            \[\nu \propto \sqrt{V}\] 

    B)            \[\nu \propto V\]

    C)            \[\nu \propto {{V}^{3/2}}\]   

    D)            \[\nu \propto {{V}^{2}}\]

    Correct Answer: B

    Solution :

               \[E=h\nu =eV\,\Rightarrow \,\nu \propto V\]


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