JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank X Rays

  • question_answer
    If V be the accelerating voltage, then the maximum frequency of continuous X-rays is given by [NCERT 1971; CPMT 1991;                                                 MP PET 2000; RPMT 2001; MP PMT 2002]

    A)            \[\frac{eh}{V}\]                  

    B)            \[\frac{hV}{e}\]

    C)            \[\frac{eV}{h}\]                  

    D)            \[\frac{h}{eV}\]

    Correct Answer: C

    Solution :

               \[E=eV=h{{\nu }_{\max }}\,\Rightarrow \,{{\nu }_{\max }}=\frac{eV}{h}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner