question_answer

An X-ray machine has an accelerating potential difference of 25,000 volts. By calculation the shortest wavelength will be obtained as (\[h=6.62\times {{10}^{-34}}\] J?sec; e = \[1.6\times {{10}^{-19}}\]coulomb) [MP PET 1994]

A)            0.25 Å                                      

B)            0.50 Å

C)            1.00 Å                                      

D)            2.50 Å