JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank X Rays

  • question_answer
    The potential difference applied to an X-ray tube is 5kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is  [IIT-JEE (Screening) 2002] 

    A)            \[2\times {{10}^{16}}\]    

    B)            \[5\times {{10}^{16}}\]

    C)            \[1\times {{10}^{17}}\]    

    D)            \[4\times {{10}^{15}}\]

    Correct Answer: A

    Solution :

               \[i=\frac{Ne}{t}\,\Rightarrow \,\frac{N}{t}=\frac{i}{e}=\frac{3.2\times {{10}^{-3}}}{1.6\times {{10}^{-19}}}=2\times {{10}^{16}}/sec\]


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