JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank X Rays

  • question_answer
    The potential difference between the cathode and the target in a Collidge tube is 100 kV. The minimum wavelength of the X-rays emitted by the tube is                                                        [Pb. PMT 2004]

    A)            0.66 Å                                      

    B)            9.38 Å

    C)            0.246 Å                                   

    D)            0.123 Å

    Correct Answer: D

    Solution :

               \[{{\lambda }_{\min }}=\frac{hc}{eV}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 100\times {{10}^{3}}}\] \[=0.123{\AA}\]


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