A) x (Blue) = x (Green)
B) x (Blue)> x (Green)
C) x (Blue) < x (Green)
D) \[\frac{x(Blue)}{x(Green)}=\frac{5460}{4360}\]
Correct Answer: C
Solution :
Distance of nth bright fringe \[{{y}_{n}}=\frac{n\lambda D}{d}i.e.\ {{y}_{n}}\propto \lambda \] \[\therefore \frac{{{x}_{{{n}_{1}}}}}{{{x}_{{{n}_{2}}}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\Rightarrow \frac{x(Blue)}{x(Green)}=\frac{4360}{5460}\] \[\therefore \]x (Green) > x (Blue).
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