A) 4 : 1
B) 1 : 1
C) 1 : 4
D) 2 : 1
Correct Answer: A
Solution :
As \[\beta =\frac{D\lambda }{d}\Rightarrow \frac{{{\beta }_{1}}}{{{\beta }_{2}}}=\left( \frac{{{D}_{1}}}{{{D}_{2}}} \right)\ \left( \frac{{{\lambda }_{1}}}{{{\lambda }_{2}}} \right)\ \left( \frac{{{d}_{2}}}{{{d}_{1}}} \right)\] \[\Rightarrow 1=\left( \frac{{{D}_{1}}}{{{D}_{2}}} \right)\times \left( \frac{1}{2} \right)\times \left( \frac{1}{2} \right)\Rightarrow \frac{{{D}_{1}}}{{{D}_{2}}}=\frac{4}{1}\]
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