A) 0.25 mm
B) 0.1 mm
C) 1.0 mm
D) 0.01 mm
Correct Answer: C
Solution :
\[\beta =\frac{\lambda D}{d}=\frac{5\times {{10}^{-7}}\times 2}{{{10}^{-3}}}m={{10}^{-3}}m=1.0\ mm\].
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