A) \[0.15\times {{10}^{-4}}m\]
B) \[2.0\times {{10}^{-4}}m\]
C) \[1.25\times {{10}^{-4}}m\]
D) \[2.5\times {{10}^{-4}}m\]
Correct Answer: D
Solution :
\[\beta =\frac{\lambda D}{d}\]\[\Rightarrow \frac{{{\beta }_{2}}}{{{\beta }_{1}}}=\frac{{{\lambda }_{2}}{{D}_{2}}{{d}_{1}}}{{{\lambda }_{1}}{{D}_{1}}{{d}_{2}}}\]\[\Rightarrow {{\beta }_{2}}=2.5\times {{10}^{-4}}m\].
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