A) 2 fringes upward
B) 2 fringes downward
C) 10 fringes upward
D) None of these
Correct Answer: A
Solution :
Shift \[=\frac{\beta }{\lambda }(\mu -1)\ t=\frac{\beta }{(5000\times {{10}^{-10}})}(1.5)\times 2\times {{10}^{-6}}=2\beta \] i.e., 2 fringes upwards.
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