A) 4.0 mm
B) 3.5 mm
C) 3.0 mm
D) 2.5 mm
Correct Answer: B
Solution :
Separation \[{{n}^{th}}\]bright fringe and central maxima is \[{{x}_{n}}=\frac{n\lambda D}{d}\] So, \[{{x}_{3}}=\frac{3\times 6000\times {{10}^{-10}}\times 1}{0.5\times {{10}^{-3}}}=3.5\,mm.\]
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