JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    In Young's double slit experiment, if the slit widths are in the ratio 1 : 9, then the ratio of the intensity at minima to that at maxima will be                                                             [MP PET 1987]

    A)            1    

    B)            1/9

    C)            1/4

    D)            1/3

    Correct Answer: C

    Solution :

                       Slit width ratio = 1 : 9                    Since slit width ratio is the ratio of intensity and intensity\[\propto \](amplitude)2                    \[\therefore {{I}_{1}}:{{I}_{2}}=1:9\]                    \[\Rightarrow a_{1}^{2}:a_{2}^{2}=1:9\Rightarrow {{a}_{1}}:{{a}_{2}}=1:3\]            \[{{I}_{\max }}={{({{a}_{1}}+{{a}_{2}})}^{2}},\ \ {{I}_{\min }}={{({{a}_{1}}-{{a}_{2}})}^{2}}\Rightarrow \frac{{{I}_{\min }}}{{{I}_{\max }}}=\frac{1}{4}\]


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