JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    In Young's double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be     [RPMT 1997]

    A) \[5000\,\,{AA}\]               

    B) \[6000\,\,{AA}\]

    C) \[7000\,\,{AA}\]               

    D) \[8000\,\,{AA}\]

    Correct Answer: A

    Solution :

    By using \[{{x}_{n}}=\frac{n\,\lambda \,D}{d}\] \[\Rightarrow (5\times {{10}^{-3}})=\frac{10\times \lambda \times 1}{(1\times {{10}^{-3}})}\Rightarrow \lambda =5\times {{10}^{-7}}m\]\[=5000\,{AA}\]


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