A) 62
B) 67
C) 85
D) 99
Correct Answer: D
Solution :
\[({{n}_{1}}{{\lambda }_{1}}={{n}_{2}}{{\lambda }_{2}})\] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\Rightarrow \frac{{{n}_{1}}}{92}=\frac{5898}{5461}\Rightarrow {{n}_{1}}=99\]
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