A) 0.08°
B) 0.16°
C) 0.20°
D) 0.313°
Correct Answer: D
Solution :
Angular position of first dark fringe \[\theta =\frac{\lambda }{d}=\frac{5460\times {{10}^{-10}}}{0.1\times {{10}^{-3}}}\times \frac{180}{\pi }\] (in degree) = 0.313°You need to login to perform this action.
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