A) 3 cm
B) 0.011 cm
C) 2 cm
D) 4 cm
Correct Answer: B
Solution :
\[\beta =\frac{(a+b)\lambda }{2a(\mu -1)\alpha }\] where a = distance between source and biprism = 0.3 m b = distance between biprism and screen = 0.7 m. a = Angle of prism = 1°, m = 1.5, \[\lambda \]= 6000 ´ 10?10 m Hence, \[\beta =\frac{(0.3+0.7)\times 6\times {{10}^{-7}}}{2\times 0.3(1.5-1)\times ({{1}^{o}}\times \frac{\pi }{180})}\] = 1.14 ´ 10?4 m = 0.0114 cm.You need to login to perform this action.
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