A) 4 : 1
B) 3 : 1
C) 2 : 1
D) 1 : 1
Correct Answer: B
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{\left( \frac{{{a}_{1}}}{{{a}_{2}}}+1 \right)}^{2}}}{{{\left( \frac{{{a}_{1}}}{{{a}_{2}}}-1 \right)}^{2}}}=\frac{4}{1}\Rightarrow \frac{{{a}_{1}}}{{{a}_{2}}}=\frac{3}{1}\]
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