JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    In the Young?s double slit experiment with sodium light. The slits are 0.589 m a part. The angular separation of the third maximum from  the central maximum will be (given l = 589 mm)                                              [Pb. PMT 2002]

    A)            \[{{\sin }^{-1}}(0.33\times {{10}^{8}})\]                       

    B)            \[{{\sin }^{-1}}(0.33\times {{10}^{-6}})\]

    C)            \[{{\sin }^{-1}}(3\times {{10}^{-8}})\]                            

    D)            \[{{\sin }^{-1}}(3\times {{10}^{-6}})\]

    Correct Answer: D

    Solution :

                       Using relation, \[d\sin \theta =n\lambda \Rightarrow \sin \theta =\frac{n\lambda }{d}\] For n = 3, \[\sin \theta =\frac{3\lambda }{d}=\frac{3\times 589\times {{10}^{-9}}}{0.589}\]                          \[=3\times {{10}^{-6}}\]or \[\theta ={{\sin }^{-1}}(3\times {{10}^{-6}})\]


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