A) 0.65 mm
B) 1.63 mm
C) 3.25 mm
D) 4.88 mm
Correct Answer: B
Solution :
Distance between \[{{n}^{th}}\] Bright fringe and \[{{m}^{th}}\] dark fringe \[(n>m)\] \[\Delta x=\left( n-m+\frac{1}{2} \right)\beta =\left( 5-3+\frac{1}{2} \right)\times \frac{6.5\times {{10}^{-7}}\times 1}{1\times {{10}^{-3}}}\] =\[1.63\,mm\]
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