A) Remain unshifted
B) Shift downward by nearly two fringes
C) Shift upward by nearly two fringes
D) Shift downward by 10 fringes
Correct Answer: C
Solution :
If shift is equal to n fringes width, then \[n=\frac{(\mu -1)t}{\lambda }=\frac{(1.5-1)\times 2\times {{10}^{-6}}}{500\times {{10}^{-9}}}=\frac{1}{500}\times {{10}^{3}}=2\] Since a thin film is introduced in upper beam. So shift will be upward.
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