A) 0 cm
B) 5 cm
C) 10 cm
D) 15 cm
Correct Answer: B
Solution :
Lateral displacement of fringes =\[\frac{\beta }{\lambda }(\mu -1)\,t\] \[=\frac{1\times {{10}^{-3}}}{600\times {{10}^{-9}}}(1.5-1)\times 0.06\times {{10}^{-3}}\]\[=\frac{1}{20}m\]\[=5\,cm.\]You need to login to perform this action.
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