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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    The area of cross-section of a wire of length 1.1 metre is 1 mm2. It is loaded with 1 kg. If Young's modulus of copper is \[1.1\times {{10}^{11}}\,N/{{m}^{2}}\], then the increase in length will be (If \[g=10\,m/{{s}^{2}})\]          [MP PET 1989]

    A) 0.01 mm

    B)                             0.075 mm

    C)                 0.1 mm

    D)                             0. 15 mm

    Correct Answer: C

    Solution :

        \[l=\frac{mgL}{AY}=\frac{1\times 10\times 1.1}{1.1\times {{10}^{11}}\times {{10}^{-6}}}m=0.1\ mm\]


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