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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    If Young's modulus of iron is \[2\times {{10}^{11}}\,N/{{m}^{2}}\] and the interatomic spacing between two molecules is \[3\times {{10}^{-10}}\]metre, the interatomic force constant  is                                 [JIPMER 1978]

    A) 60 N/m

    B)                                             120 N/m

    C)                 30 N/m

    D)                             180 N/m

    Correct Answer: A

    Solution :

        Interatomic force constant \[K=Y\times {{r}_{0}}\]                                   \[=2\times {{10}^{11}}\times 3\times {{10}^{-10}}=60\ N/m\]


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