question_answer

In CGS system, the Young's modulus of a steel wire is \[2\times {{10}^{12}}\]. To double the length of a wire of unit cross-section area, the force required is                                              [MP PMT 1989]

A)                 \[4\times {{10}^{6}}\]dynes

B)                             \[2\times {{10}^{12}}\]dynes

C)                 \[2\times {{10}^{12}}\]newtons

D)                             \[2\times {{10}^{8}}\]dynes