A) 0.5 cm
B) 2 cm
C) 4 cm
D) 8 cm
Correct Answer: C
Solution :
\[l=\frac{FL}{AY}\Rightarrow l\propto \frac{1}{{{r}^{2}}}\] (F, L and Y are constant) \[\frac{{{l}_{2}}}{{{l}_{1}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}={{(2)}^{2}}=4\]\[\Rightarrow {{l}_{2}}=4{{l}_{1}}=4cm\]You need to login to perform this action.
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