A) \[Y=\frac{9\eta K}{\eta +3K}\]
B) \[\frac{9YK}{Y+3K}\]
C) \[Y=\frac{9\eta K}{3+K}\]
D) \[Y=\frac{3\eta K}{9\eta +K}\]
Correct Answer: A
Solution :
\[Y=3K(1-2\sigma )\text{ and}\ Y=2\eta (1+\sigma )\] Eliminating \[\sigma \] we get \[Y=\frac{9\eta K}{\eta +3K}\]
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