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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    Steel and copper wires of same length are stretched by the same weight one after the other. Young's modulus of steel and copper are \[2\times {{10}^{11}}\,N/{{m}^{2}}\] and \[1.2\times {{10}^{11}}\,N/{{m}^{2}}\]. The ratio of increase in length                                 [MP PET 1984]

    A)                 \[\frac{2}{5}\]       

    B)                 \[\frac{3}{5}\]

    C)                 \[\frac{5}{4}\]       

    D)                 \[\frac{5}{2}\]

    Correct Answer: B

    Solution :

        \[l=\frac{FL}{AY}\Rightarrow \frac{{{l}_{S}}}{{{l}_{cu}}}=\frac{{{Y}_{cu}}}{{{Y}_{S}}}\](F,L and Y are constant)            \ \[\frac{{{l}_{s}}}{{{l}_{cu}}}=\frac{1.2\times {{10}^{11}}}{2\times {{10}^{11}}}=\frac{3}{5}\]


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