A) \[1\times {{10}^{-2}}\,{{m}^{2}}\]
B) \[1.4\times {{10}^{-3}}\,{{m}^{2}}\]
C) \[3.5\times {{10}^{-3}}\,{{m}^{2}}\]
D) \[7.1\times {{10}^{-4}}\,{{m}^{2}}\]
Correct Answer: D
Solution :
\[Y=\frac{F/A}{\text{strain}}\Rightarrow A=\frac{F}{Y\times \text{strain}}\]= \[\frac{{{10}^{4}}}{7\times {{10}^{9}}\times 0.002}\] = \[\frac{1}{14}\times {{10}^{-2}}\]\[=7.1\times {{10}^{-4}}{{m}^{2}}\]
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