JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
     Two wires of copper having the length in the ratio 4 : 1 and their radii ratio as 1 : 4 are stretched by the same force. The ratio of longitudinal strain in the two will be

    A) 1 : 16     

    B)                 16 : 1

    C)                 1 : 64     

    D)                 64 : 1          

    Correct Answer: B

    Solution :

        \[\text{strain}\propto \text{stress}\propto \frac{\text{F}}{\text{A}}\] Ratio of strain =\[\frac{{{A}_{2}}}{{{A}_{1}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}={{\left( \frac{4}{1} \right)}^{2}}=\frac{16}{1}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner