A) \[1.2\times {{10}^{11}}\]
B) \[4.2\times {{10}^{11}}\]
C) \[10.8\times {{10}^{-19}}\]
D) \[2.4\times {{10}^{10}}\]
Correct Answer: A
Solution :
\[Y=\frac{3.6\times {{10}^{-9}}N/{\AA}}{3\times {{10}^{-10}}m}\]\[=1.2\times {{10}^{11}}N/{{m}^{2}}\]
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