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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    For silver, Young's modulus is \[7.25\times {{10}^{10}}\,N/{{m}^{2}}\] and Bulk modulus is \[11\times {{10}^{10}}\,N/{{m}^{2}}\]. Its Poisson's ratio will be

    A) ? 1          

    B)                 0.5

    C)                 0.39       

    D)                 0.25

    Correct Answer: C

    Solution :

        \[Y=3K(1-2\sigma )\]             \[\sigma =\frac{3K-Y}{6K}\]=\[\frac{3\times 11\times {{10}^{10}}-7.25\times {{10}^{10}}}{6\times 11\times {{10}^{10}}}\]\[\Rightarrow \sigma =0.39\]


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