A) \[4\times {{10}^{3}}\]N
B) \[16\times {{10}^{3}}\]N
C) \[\frac{1}{4}\times {{10}^{3}}\]N
D) \[\frac{1}{16}\times {{10}^{3}}\]N
Correct Answer: B
Solution :
\[F=Y\times A\times \frac{l}{L}\]Þ\[F\propto {{r}^{2}}\](Y,l and L are constant) If diameter is made four times then force required will be 16 times. i.e. 16 × 103 N
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